LAST UPDATED ON: SEPTEMBER 17, 2024
Program to perform addition and subtraction of Matrices in C
Below is a program to perform Addition and Subtraction on two matrices.
\n
is used to take the control to the next row.
\t
is used to take control 5 spaces(tab) ahead.
#include<stdio.h>
int main()
{
printf("\n\n\t\tStudytonight - Best place to learn\n\n\n");
int n, m, c, d, first[10][10], second[10][10], sum[10][10], diff[10][10];
printf("\nEnter the number of rows and columns of the first matrix \n\n");
scanf("%d%d", &m, &n);
printf("\nEnter the %d elements of the first matrix \n\n", m*n);
for(c = 0; c < m; c++) // to iterate the rows
for(d = 0; d < n; d++) // to iterate the columns
scanf("%d", &first[c][d]);
printf("\nEnter the %d elements of the second matrix \n\n", m*n);
for(c = 0; c < m; c++) // to iterate the rows
for(d = 0; d < n; d++) // to iterate the columns
scanf("%d", &second[c][d]);
/*
printing the first matrix
*/
printf("\n\nThe first matrix is: \n\n");
for(c = 0; c < m; c++) // to iterate the rows
{
for(d = 0; d < n; d++) // to iterate the columns
{
printf("%d\t", first[c][d]);
}
printf("\n");
}
/*
printing the second matrix
*/
printf("\n\nThe second matrix is: \n\n");
for(c = 0; c < m; c++) // to iterate the rows
{
for(d = 0; d < n; d++) // to iterate the columns
{
printf("%d\t", second[c][d]);
}
printf("\n");
}
/*
finding the SUM of the two matrices
and storing in another matrix sum of the same size
*/
for(c = 0; c < m; c++)
for(d = 0; d < n; d++)
sum[c][d] = first[c][d] + second[c][d];
// printing the elements of the sum matrix
printf("\n\nThe sum of the two entered matrices is: \n\n");
for(c = 0; c < m; c++)
{
for(d = 0; d < n; d++)
{
printf("%d\t", sum[c][d]);
}
printf("\n");
}
/*
finding the DIFFERENCE of the two matrices
and storing in another matrix difference of the same size
*/
for(c = 0; c < m; c++)
for(d = 0; d < n; d++)
diff[c][d] = first[c][d] - second[c][d];
// printing the elements of the diff matrix
printf("\n\nThe difference(subtraction) of the two entered matrices is: \n\n");
for(c = 0; c < m; c++)
{
for(d = 0; d < n; d++)
{
printf("%d\t", diff[c][d]);
}
printf("\n");
}
printf("\n\n\t\t\tCoding is Fun !\n\n\n");
return 0;
}
Output: