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No need for jQuery, use:
***JSON.stringify(countries); ***
4 years ago
The best method I have found so far is the jQuery appear plugin. Works like a charm.
Mimics a custom "appear" event, which fires when an element scrolls into view or otherwise becomes visible to the user.
***$('#foo').appear(function() {
$(this).text('Hello world');
});***
This plugin can be used to prevent unnecessary requests for content that's hidden or outside the viewable area.
4 years ago
If you'd like to get the option with a value of 2, use
***$("#list option[value='2']").text();***
If you'd like to get whichever option is currently selected, use
***$("#list option:selected").text();***
4 years ago
I found this to be the simplest way:
***myInteger.ToString("N0")***
4 years ago
A general solution to convert from byte array to string when you don't know the encoding:
***static string BytesToStringConverted(byte[] bytes)
{
using (var stream = new MemoryStream(bytes))
{
using (var streamReader = new StreamReader(stream))
{
return streamReader.ReadToEnd();
}
}
}***
4 years ago
You may be looking to do this:
***System.IO.Path.GetDirectoryName(
System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase)***
4 years ago
.NET 4.0 has a built-in library to do this:
***using System.Web.Script.Serialization;
JavaScriptSerializer jss = new JavaScriptSerializer();
var d = jss.Deserialize(str);***
4 years ago
Procedural sample:
***.GroupBy(x => new { x.Column1, x.Column2 })***
4 years ago
Assuming **value** is a **double**, you can do:
***(double)Math.round(value * 100000d) / 100000d***
That's for 5 digits precision. The number of zeros indicate the number of decimals.
4 years ago
I found a one-line solution from the good old Apache Commons Lang library.
**ArrayUtils.addAll(T[], T...)**
Code:
***String[] both = ArrayUtils.addAll(first, second);***
4 years ago
A very lean solution based on Scanner:
***Scanner scanner = new Scanner( new File("poem.txt") );
String text = scanner.useDelimiter("\\A").next();
scanner.close(); // Put this call in a finally block***
Or, if you want to set the charset:
***Scanner scanner = new Scanner( new File("poem.txt"), "UTF-8" );
String text = scanner.useDelimiter("\\A").next();
scanner.close(); // Put this call in a finally block***
Or, with a try-with-resources block, which will call **scanner.close()** for you:
***try (Scanner scanner = new Scanner( new File("poem.txt"), "UTF-8" )) {
String text = scanner.useDelimiter("\\A").next();
}***
Remember that the **Scanner** constructor can throw an **IOException**. And don't forget to import **java.io** and **java.util**.
4 years ago
The version number shown describes the version of the JRE the class file is compatible with.
The reported major numbers are:
***
Java SE 17 = 61,
Java SE 16 = 60,
Java SE 15 = 59,
Java SE 14 = 58,
Java SE 13 = 57,
Java SE 12 = 56,
Java SE 11 = 55,
Java SE 10 = 54,
Java SE 9 = 53,
Java SE 8 = 52,
Java SE 7 = 51,
Java SE 6.0 = 50,
Java SE 5.0 = 49,
JDK 1.4 = 48,
JDK 1.3 = 47,
JDK 1.2 = 46,
JDK 1.1 = 45
***
(Source: Wikipedia)

To fix the actual problem you should try to either run the Java code with a newer version of Java JRE or specify the target parameter to the Java compiler to instruct the compiler to create code compatible with earlier Java versions.

For example, in order to generate class files compatible with Java 1.4, use the following command line:

***javac -target 1.4 HelloWorld.java***
With newer versions of the Java compiler you are likely to get a warning about the bootstrap class path not being set. More information about this error is available in a blog post **New javac warning for setting an older source without bootclasspath.**
4 years ago