If you look at the docs for **bytes**, it points you to **bytearray:**
***bytearray([source[, encoding[, errors]]])
Return a new array of bytes. The bytearray type is a mutable sequence of integers in the range 0 <= x < 256. It has most of the usual methods of mutable sequences, described in Mutable Sequence Types, as well as most methods that the bytes type has, see Bytes and Byte Array Methods.
The optional source parameter can be used to initialize the array in a few different ways:
If it is a string, you must also give the encoding (and optionally, errors) parameters; bytearray() then converts the string to bytes using str.encode().
If it is an integer, the array will have that size and will be initialized with null bytes.
If it is an object conforming to the buffer interface, a read-only buffer of the object will be used to initialize the bytes array.
If it is an iterable, it must be an iterable of integers in the range 0 <= x < 256, which are used as the initial contents of the array.
Without an argument, an array of size 0 is created.***
So bytes can do much more than just encode a string. It's Pythonic that it would allow you to call the constructor with any type of source parameter that makes sense.
For encoding a string, I think that **some_string.encode(encoding)** is more Pythonic than using the constructor, because it is the most self documenting -- "take this string and encode it with this encoding" is clearer than **bytes(some_string, encoding)** -- there is no explicit verb when you use the constructor.
Edit: Checked the Python source. If you pass a unicode string to **bytes** using CPython, it calls **PyUnicode_AsEncodedString**, which is the implementation of encode; so you're just skipping a level of indirection if you call **encode** yourself.
