What is the >>>= operator in C?

Question

What is the >>>= operator in C?

Given by a colleague as a problem, I cannot find out how this C program really compiles and runs. What is this >>>= operator and the strange 1P1 literal? I have tested in Clang and GCC. There are no signs and the output is "???"

#include <stdio.h>



int main()

{

    int a[2]={ 10, 1 };



    while( a[ 0xFULL?'\0':-1:>>>=a<:!!0X.1P1 ] )

        printf("?");



    return 0;

}

literals obfuscation

4 years ago by Amit8z4mc

1 Answer

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**sandhya6gczb** · Answer 1 · 2021-06-16T13:17:55

This is a more readable version:



while( a[ 0xFULL ? '\0' : -1 ] >>= a[ !!0X.1P1 ] )

and an even more readable version, replacing the expressions in the [] for the values they resolve to:



while( a[0] >>= a[1] )

Replacing a[0] and a[1] for their values should make it easy to figure out what the loop is doing, i.e. the equivalent of:



int i = 10;

while( i >>= 1)

which is simply performing (integer) division by 2 in each iteration, producing the sequence 5, 2, 1.

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What is the >>>= operator in C?

1 Answer

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