Open() in Python does not create a file if it doesn't exist

Question

Open() in Python does not create a file if it doesn't exist

What is the most ideal approach to open a file as reading/writing on the off chance that it exists, or on the off chance that it doesn't, make it and open it as reading/writing? From what I read, record = open('myfile.dat', 'rw') ought to do this, correct?

It isn't working for me (Python 2.6.2) and I'm contemplating whether it is a variant issue, or shouldn't work like that for sure.

The main concern is, I simply need an answer to the issue. I'm interested in the other stuff, yet all I need is a pleasant method to do the initial part.

linux python

4 years ago by Bharatv4tg1

2 Answers

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**ninja01** · Answer 1 · 2021-05-21T15:40:13

ninja01

You should use open with the w+ mode:



file = open('myfile.dat', 'w+')

4 years ago

**RoliMishra** · Answer 2 · 2021-05-24T16:05:36

Good practice is to use the following:

import os



writepath = 'some/path/to/file.txt'



mode = 'a' if os.path.exists(writepath) else 'w'

with open(writepath, mode) as f:

    f.write('Hello, world!\n')

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Open() in Python does not create a file if it doesn't exist

2 Answers

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