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How to use GROUP BY to concatenate strings in SQL Server?

How do I get:

id       Name       Value
1 A 4
1 B 8
2 C 9

to

id          Column
1 A:4, B:8
2 C:9
by

3 Answers

akshay1995
No CURSOR, WHILE loop, or User-Defined Function needed.

Just need to be creative with FOR XML and PATH.

[Note: This solution only works on SQL 2005 and later. Original question didn't specify the version in use.]

CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

SELECT
[ID],
STUFF((
SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX))
FROM #YourTable
WHERE (ID = Results.ID)
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID

DROP TABLE #YourTable
sandhya6gczb
If it is SQL Server 2017 or SQL Server Vnext, SQL Azure you can use string_agg as below:

select id, string_agg(concat(name, ':', [value]), ', ')
from #YourTable
group by id
pankajshivnani123
Another option using Sql Server 2005 and above

---- test data
declare @t table (OUTPUTID int, SCHME varchar(10), DESCR varchar(10))
insert @t select 1125439 ,'CKT','Approved'
insert @t select 1125439 ,'RENO','Approved'
insert @t select 1134691 ,'CKT','Approved'
insert @t select 1134691 ,'RENO','Approved'
insert @t select 1134691 ,'pn','Approved'

---- actual query
;with cte(outputid,combined,rn)
as
(
select outputid, SCHME + ' ('+DESCR+')', rn=ROW_NUMBER() over (PARTITION by outputid order by schme, descr)
from @t
)
,cte2(outputid,finalstatus,rn)
as
(
select OUTPUTID, convert(varchar(max),combined), 1 from cte where rn=1
union all
select cte2.outputid, convert(varchar(max),cte2.finalstatus+', '+cte.combined), cte2.rn+1
from cte2
inner join cte on cte.OUTPUTID = cte2.outputid and cte.rn=cte2.rn+1
)
select outputid, MAX(finalstatus) from cte2 group by outputid

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