🤩 New Cool Developer Tools for you. Explore →
FREE JavaScript Video Series Start Learning →
FLAT 75% OFF All Interactive courses at flat ₹250 / $3.25 only. HURRRRRY!! Explore now
  Signup/Sign In
Tests
MCQs to test your knowledge.
Forum
Engage with the community.
Compilers
Compilers to execute code in browser.
← Back to Questions
Ask Question
Not satisfied by the Answer? Still looking for a better solution?
Ask Question

How to solve PHP error Notice: Array to string conversion

A PHP file that tries to echo a $_POST gets an error, here is the code:


echo "<html>";

echo "<body>";

for($i=0; $i<5;$i++){

    echo "<input name='C[]' value='$Texting[$i]' " . 

         "style='background-color:#D0A9F5;'></input>";

}

echo "</body>";

echo "</html>";

echo '<input type="submit" value="Save The Table" name="G"></input>'

Here is the code to echo the POST.



if(!empty($_POST['G'])){

    echo $_POST['C'];

}

But when the code runs I get an error like:


Notice: Array to string conversion in 

C:\xampp\htdocs\PHIS\FinalSubmissionOfTheFormPHP.php on line 8

What does this error mean and how do I fix it?
html php
by

3 Answers

Kajalsi45d
If you send a PHP array into a function that expects a string like: echo or print, then the PHP interpreter will convert your array to the literal string Array, throw this Notice and keep going. For example:


php> print(array(1,2,3))



PHP Notice:  Array to string conversion in 

/usr/local/lib/python2.7/dist-packages/phpsh/phpsh.php(591) :

eval()'d code on line 1

Array

In this case, the function print dumps the literal string: Array to stdout and then logs the Notice to stderr and keeps going.

Another example in a PHP script:


<?php

    $stuff = array(1,2,3);

    print $stuff;  //PHP Notice:  Array to string conversion in yourfile on line 3

?>
Bharatgxwzm
You are using <input name='C[]' in your HTML. This creates an array in PHP when the form is sent.

You are using echo $_POST['C']; to echo that array - this will not work, but instead, emit that notice and the word "Array".

Depending on what you did with the rest of the code, you should probably use echo $_POST['C'][0];
kshitijrana14 
<?php

ob_start();

var_dump($_POST['C']);

$result = ob_get_clean();

?>

if you want to capture the result in a variable

Login / Signup to Answer the Question.

LoginSignup