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How to remove item from array by value?

Is there a strategy to eliminate an item from a JavaScript array?

Given an array:
var ary = ['three', 'seven', 'eleven'];


I might want to accomplish something like:
removeItem('seven', ary);


I've investigated splice() yet that solitary eliminates by the position number, though I need something to eliminate an item by its value.
array java
by

2 Answers

akshay1995
You can use the indexOf method like this:


var index = array.indexOf(item);

if (index !== -1) {

  array.splice(index, 1);

}
kshitijrana14
This can be a global function or a method of a custom object, if you aren't allowed to add to native prototypes. It removes all of the items from the array that match any of the arguments.
Array.prototype.remove = function() {

    var what, a = arguments, L = a.length, ax;

    while (L && this.length) {

        what = a[--L];

        while ((ax = this.indexOf(what)) !== -1) {

            this.splice(ax, 1);

        }

    }

    return this;

};



var ary = ['three', 'seven', 'eleven'];



ary.remove('seven');



/  returned value: (Array)

three,eleven

*/

To make it a global-

function removeA(arr) {

    var what, a = arguments, L = a.length, ax;

    while (L > 1 && arr.length) {

        what = a[--L];

        while ((ax= arr.indexOf(what)) !== -1) {

            arr.splice(ax, 1);

        }

    }

    return arr;

}

var ary = ['three', 'seven', 'eleven'];

removeA(ary, 'seven');





/*  returned value: (Array)

three,eleven

/

And to take care of IE8 and below-

if(!Array.prototype.indexOf) {

    Array.prototype.indexOf = function(what, i) {

        i = i || 0;

        var L = this.length;

        while (i < L) {

            if(this[i] === what) return i;

            ++i;

        }

        return -1;

    };

}

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