Find string appears s2 in s1

Question

Find string appears s2 in s1

s1 = 'timisverytimidbuthasnotime'
s2 = 'tim'
Write a python function to find out no. of times the string s2 appears in string s1 ? without inbuilt function

dataframe python

8 months ago by ganeshkavhar

1 Answer

Login / Signup to Answer the Question.

Login Signup

**iamabhishek** · Answer 1 · 2024-04-24T04:13:36

Try this:



def count_occurrences(s1, s2):

    count = 0

    for i in range(len(s1) - len(s2) + 1):

        if s1[i:i+len(s2)] == s2:

            count += 1

    return count



s1 = 'timisverytimidbuthasnotime'

s2 = 'tim'

print(count_occurrences(s1, s2))  # Output will be 2

C TUTORIAL

C PROGRAMS

INTERVIEW TESTS

EXECUTE CODE

C++ TUTORIAL

C++ PROGRAMS

INTERVIEW TESTS

EXECUTE CODE

PYTHON TUTORIAL

PYTHON HOW TOS

INTERVIEW TESTS

EXECUTE CODE

JAVA TUTORIAL

JAVA CODE EXAMPLES

SPRING TUTORIAL

MORE IN JAVA

COMPUTER ARCHITECTURE

COMPUTER NETWORK

OPERATING SYSTEM

DBMS & SQL

PL/SQL

MongoDB

EXECUTE SQL

ANDROID DEVELOPMENT

GO LANGUAGE

LINUX

DOCKER

HTML TAGS (A to Z)

CSS REFERENCES

SASS/SCSS

KOTLIN

GAME DEVELOPMENT

PHP

GIT GUIDE

JAVASCRIPT

ADVANCED DSA

Find string appears s2 in s1

1 Answer

Login / Signup to Answer the Question.