Extract file basename without path and extension in bash

You don't have to call the external basename command. Instead, you could use the following commands:

$ s=/the/path/foo.txt

$ echo "${s##/}"

foo.txt

$ s=${s##*/}

$ echo "${s%.txt}"

foo

$ echo "${s%.}"

foo

Note that this solution should work in all recent (post 2004) POSIX compliant shells, (e.g. bash, dash, ksh, etc.).

4 years ago

The basename command has two different invocations; in one, you specify just the path, in which case it gives you the last component, while in the other you also give a suffix that it will remove. So, you can simplify your example code by using the second invocation of basename. Also, be careful to correctly quote things:

fbname=$(basename "$1" .txt)

echo "$fbname"

4 years ago

A combination of basename and cut works fine, even in case of double ending like .tar.gz:

fbname=$(basename "$fullfile" | cut -d. -f1)

4 years ago